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IBM C9050-042 Exam Syllabus Topics:

IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Which code should NOT be split out into separate subroutines?

A) Dead code in a program.
B) Redundant code in a program.
C) Code which must be available on different platforms.
D) Redundant code in a group otprograms.

2. Program A calls program B with PC as a parameter defined BIN FIXED (31 .0). Program B sets PC as
follows:
0 OK
4 WARNING
8 ERROR
Which of the following is the most appropriate statement for testing the PC variable?

A) IF (RC >4) THEN PUT SKIP LIST('ERROR IN B');
ELSE PUT SKIP LIST('UNKNOWN VALUE FROM B');
B) SELECT (RC); WHEN (0,4); WHEN (8) PUT SKIP LIST ('ERROR IN B');
OTHERWISE PUT SKIP LIST('UNKNOWN VALUE FROM B');
END;
C) IF (RC ^= 0) & (RC ^= 4) THEN PUT SKIP LIST('ERROR IN B');
ELSE IF RC> 8 THEN PUT SKIP LIST('UNKNOWN VALUE FROM B);
D) SELECT (RC);
WHEN (0, 4);
OTHERWISE
PUT SKIP LIST('UNKNOWN VALUE FROM B');
END;

3. Which of the following compile list sections would be used to find the location of a static variable in a
dump?

A) Attribute/Xref Table
B) Table of Offsets and Statement Numbers
C) Source Listing
D) Storage Offset Listing

4. What happens after executing the following code?
DCL OUTFILE FILE RECORD OUTPUT;
DCLP PTR;
DCL I BIN FIXED(31);
DCL A BIN FIXED(31) BASED(P);
DO I = 1 TO 10;
LOCATE A FILE(OUTFILE) SET(P);
A = I;
END;
CLOSE FILE(OUTFILE);

A) 9 records will be written with value 1 to 9.
B) 9 records will be written with value 2 to 10.
C) 10 records will be written with first record value undefined.
D) 10 records will be written with value 1 to 10.

5. Given the following declaration, W has to be assigned to C.
How can a CONVERSION condition be
avoided?
DCL C CHAR(1);
DCL W WIDECHAR(1);

A) IFW ^= CHAR(W)THEN
PUT ('Widechar not is a valid char!');
ELSE
C = W;
B) IFW >128THEN
PUT ('Widechar is not a valid char!');
ELSE
C = W;
C) IF RANK(W)> 127 THEN
PUT ('Widechar is not a valid char!');
ELSE
C = W;
D) IF WCHARVAL(W) > 128 THEN
PUT ('Widechar is not a valid char!');
ELSE
C = W;

Solutions: